Question about HD52W59 HDTV Projection Television
find two consecutive even integers whose product is 1,520 2n = 1st even integer 2n + 2 = 2nd even integer Product = 2n(2n + 2) = 4n^2 + 4n = 4(n^2 + n) 1520 = 4(n^2 + n) 1520/4 = 4(n^2 + n)/4 380 = ...
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